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JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The density of \(3\,M\) solution of sodium chloride is \(1.252\,g\,mL^{-1}\) . The molality of the solution will be ............. \(\mathrm{m}\) (molar mass, \(NaCl = 585\,g\,mol^{-1}\) )
- A \(260\)
- B \(2.18\)
- C \(2.79\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(2.79\)
Step-by-step Solution
Detailed explanation
The relation between molarity \((M)\) and molality \((m)\) is \(d\, = \,M\,\left( {\frac{1}{m}\, + \,\frac{{{M_2}}}{{1000}}} \right)\,,\,{M_2}\, = \) Mol. mass of solute On putting value \(1.252\, = \,3\left( {\frac{1}{m}\, + \,\frac{{58.5}}{{1000}}} \right)\) on solving…
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