JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
When \(800\,mL\) of \(0.5\,M\) nitric acid is heated in a beaker, its volume is reduced to half and \(11.5\,g\) of nitric acid is evaporated. The molarity of the remaining nitric acid solution is \(x \times 10^{-2}\,M\).(Nearest Integer)(Molar mass of nitric acid is \(63\,g\,mol ^{-1}\) )
- A \(51\)
- B \(52\)
- C \(53\)
- D \(54\)
Answer & Solution
Correct Answer
(D) \(54\)
Step-by-step Solution
Detailed explanation
\(n _{ HNO _{3}}=0.5 \times 0.8\) \(=0.4 mole\) \(\left( n _{ HNO _{3}}\right)_{\text {remains }}=0.4\) \(=0.4-0.1825\) \(=0.2175\) \(Molarity\) \(=\frac{0.2175}{400} \times 1000\) \(=\frac{0.2175}{0.4}\) \(=0.5437\,mole / lit\) \(\simeq 0.54 mole / lit\)…
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