JEE Advanced · Physics · 21. EMI
In the figure below, the switches are closed simultaneously at and a current starts to flow in the circuit. Both the batteries have the same magnitude of the electromotive force (emf) and the polarities are as indicated in the figure. Ignore mutual inductance between the inductors. The current I in the middle wire reaches its maximum magnitude time . Which of the following statements is (are) true?

- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
The current in the middle, , as shown in the figure above has a maximum value,
Using the equation of current decay in an circuit, for the given values in the figure above,
\(i=\left(i_2-i_1\right)=\frac{V}{R}\left[1-e^{-\left(\frac{R}{2 L}\right) t}\right]-\) \(\frac{V}{R}\left[1-e^{\left(-\frac{R}{L}\right) t}\right] \)
\( \frac{V}{R}\left[e^{\left(-\frac{R}{L}\right) t}-e^{\left(-\frac{R}{2 L}\right) t}\right]\)
For
time when I is maximum
Using the equation of current decay in an circuit, for the given values in the figure above,
\(i=\left(i_2-i_1\right)=\frac{V}{R}\left[1-e^{-\left(\frac{R}{2 L}\right) t}\right]-\) \(\frac{V}{R}\left[1-e^{\left(-\frac{R}{L}\right) t}\right] \)
\( \frac{V}{R}\left[e^{\left(-\frac{R}{L}\right) t}-e^{\left(-\frac{R}{2 L}\right) t}\right]\)
For
time when I is maximum
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