JEE Advanced · Mathematics · 21. ITF
Considering only the principal values of the inverse trigonometric functions, the value of \(\tan \left(\sin ^{-1}\left(\frac{3}{5}\right)-2 \cos ^{-1}\left(\frac{2}{\sqrt{5}}\right)\right)\) is
- A \(\frac{7}{24}\)
- B \(\frac{-7}{24}\)
- C \(\frac{-5}{24}\)
- D \(\frac{5}{24}\)
Answer & Solution
Correct Answer
(B) \(\frac{-7}{24}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Rightarrow \tan \left(\tan ^{-1}\left(\frac{3}{4}\right)-2 \tan ^{-1}\left(\frac{1}{2}\right)\right) \\ & \Rightarrow \tan \left(\tan ^{-1}\left(\frac{3}{4}\right)-\tan ^{-1}\left(\frac{2 \times \frac{1}{2}}{1-\frac{1}{4}}\right)\right) \\ & \Rightarrow \tan \left(\tan ^{-1}\left(\frac{3}{4}\right)-\tan ^{-1}\left(\frac{4}{3}\right)\right) \\ & \Rightarrow \tan \left(\tan ^{-1}\left(\frac{\frac{3}{4}-\frac{4}{3}}{1+1}\right)\right) \\ & \Rightarrow \frac{9-16}{24}=\frac{-7}{24}\end{aligned}\)
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