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JEE Advanced · Physics · 17. Electrostatics

Consider a uniform spherical charge distribution of radius R1 centred at the origin O. In this distribution, a spherical cavity of radius R2 , centred at P with distance OP=a=R1-R2 (see figure) is made. If the electric field inside the cavity at position r is E(r) , then the correct statement(s) is (are)

  1. A E is uniform, its magnitude is independent of R2 but its direction depends on r
  2. B E is uniform, its magnitude is depends on R2 and its direction depends on r
  3. C E is uniform, its magnitude is dependent of a but its direction depends on a
  4. D E is uniform and both its magnitude and direction depend on a
Verified Solution

Answer & Solution

Correct Answer

(D) E is uniform and both its magnitude and direction depend on a

Step-by-step Solution

Detailed explanation


Considering any point A inside the cavity electric field can be calculated at A by using super position principle.
\(\vec{E}_A=\left(\vec{E}_A\right)_{\text {Due to sphere without cavity }}-\) \(\left(\vec{E}_A\right)_{\text {Due to sphere of radius } R_2 \& \text { centre at } P}\)
EA=ρ3ϵ0OA=ρ3ϵ0PA
But OP+PA=OP
OA-PA=OP
EA=ρ3ϵ0OP=ρ3ϵ0a
So E.F. is independent of location of A inside the cavity.
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