JEE Advanced · Chemistry · 23. Coordination Compounds

The pair(s) of coordination complexes/ions exhibiting the same kind of isomerism is (are)

A $[Cr {({NH}_{3})}_{5} Cl] {Cl}_{2}$ and $[Cr {({NH}_{3})}_{4} {Cl}_{2}] Cl$
B ${[Co {({NH}_{3})}_{4} {Cl}_{2}]}^{+}$ and ${[Pt {({NH}_{3})}_{2} (H_{2} O) Cl]}^{+}$
C ${[Co {Br}_{2} {Cl}_{2}]}^{2 -}$ and ${[Pt {Br}_{2} {Cl}_{2}]}^{2 -}$
D $[Pt {({NH}_{3})}_{3} ({NO}_{3})] Cl$ and $[Pt {({NH}_{3})}_{3} Cl] Br$

Verified Solution

Answer & Solution

Correct Answer

(D) $[Pt {({NH}_{3})}_{3} ({NO}_{3})] Cl$ and $[Pt {({NH}_{3})}_{3} Cl] Br$

Step-by-step Solution

Detailed explanation

[Cr {({NH}_{3})}_{5} Cl] {Cl}_{2}

and

[Cr {({NH}_{3})}_{4} {Cl}_{2}] Cl

, both compounds will not show either structural or stereoisomerism.

{[Co {({NH}_{3})}_{4} {Cl}_{2}]}^{+}

and

{[Pt {({NH}_{3})}_{2} (H_{2} O) Cl]}^{+}

, Ma₄b₂ type (octahedral), Ma₂bc type (square planar) and both will show geometrical isomerism.

{[Co {Br}_{2} {Cl}_{2}]}^{2 -}

and

{[Pt {Br}_{2} {Cl}_{2}]}^{2 -}

, Ma₄b₂ type (tetrahedral), Ma₂b₂ (square planar).

[Pt {({NH}_{3})}_{3} ({NO}_{3})] Cl

and

[Pt {({NH}_{3})}_{3} Cl] Br

both will show ionisation isomerism.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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