JEE Advanced · Chemistry · 15. Solid State
The correct statement(s) regarding defects in solids is (are)
- A Frenkel defect is usually favoured by a very small difference in the sizes of cation and anion
- B Frenkel defect is a dislocation defect
- C Trapping of an electron in the lattice leads to the formation of F-centre
- D Schottky defects have no effect on the physical properties of solids
Answer & Solution
Correct Answer
(C) Trapping of an electron in the lattice leads to the formation of F-centre
Step-by-step Solution
Detailed explanation
(a) Wrong Frenkel defect is favoured when the difference in ionic radii is very large. In the given case Schottky defect is favoured.
(b) Correct Frenkel defect arises due to dislocation of smaller ion from its normal lattice point to the interstitial space.
(c) Correct When alkali metal in the gaseous state is passed over salts like \(\mathrm{NaCl}\), electrons from metal are trapped in the interstitial space giving rise to F-centre defect which is a type of Frenkel defect.
(d) Wrong Schottky defect affects physical properties of solids.
(b) Correct Frenkel defect arises due to dislocation of smaller ion from its normal lattice point to the interstitial space.
(c) Correct When alkali metal in the gaseous state is passed over salts like \(\mathrm{NaCl}\), electrons from metal are trapped in the interstitial space giving rise to F-centre defect which is a type of Frenkel defect.
(d) Wrong Schottky defect affects physical properties of solids.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Ozonolysis of produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is ______ .JEE Advanced 2021 Medium
- The electrochemical extraction of aluminium from bauxite ore involvesJEE Advanced 2022 Medium
- The pair(s) of diamagnetic ions is(are)JEE Advanced 2025 Easy
- Among the following, the surfactant that will form micelles in aqueous solution at the lowest molar concentration at ambient conditions isJEE Advanced 2008 Medium
- All the compounds listed in Column I react with water. Match the result of the respective reactions with the appropriate options listed in Column II.
JEE Advanced 2010 Medium - Paragraph:
The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by \(s\)-character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below:



Question:
Correct match of the \(\mathbf{C}-\mathbf{H}\) bonds (shown in bold) in Column \(\mathbf{J}\) with their BDE in Column \(\mathbf{K}\) is
JEE Advanced 2021 Medium
More PYQs from JEE Advanced
- Paragraph:
Football teams \(T_{1}\) and \(T_{2}\) have to play two games against each other. It is assumed that the outcomes of the two games are independent. The probabilities of \(T_{1}\) winning, drawing and losing a game against \(T_{2}\) are \(\frac{1}{2}, \frac{1}{6}\) and \(\frac{1}{3}\), respectively. Each team gets \(3\) points for a win, \(1\) point for a draw and \(0\) point for a loss in a game. Let \(X\) and \(Y\) denote the total points scored by teams \(T_{1}\) and \(T_{2}\), respectively, after two games.
Question:
\(P(X>Y)\) isJEE Advanced 2016 Easy - Paragraph :
Consider an evacuated cylindrical chamber of height \(h\) having rigid conducting plates at the ends and an insulating curved surface as shown in the figure. A number of spherical balls made of a light weight and soft material and coated with a conducting material are placed on the bottom plate. The balls have a radius \(r \ll h\). Now a high voltage source \((HV)\) is connected across the conducting plates such that the bottom plate is at \(+V_{0}\) and the top plate at \(-V_{0} .\) Due to their conducting surface, the balls will get charged, will become equipotential with the plate and are repelled by it. The balls will eventually collide with the top plate, where the coefficient of restitution can be taken to be zero due to the soft nature of the material of the balls. The electric field in the chamber can be considered to be that of a parallel plate capacitor. Assume that there are no collisions between the balls and the interaction between them is negligible. (Ignore gravity)
Question :
Which one of the following statements is correct?JEE Advanced 2016 Medium - Paragraph :
A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, \(C_{V}=2 R\). Here, \(R\) is the gas constant. Initially, each side has a volume \(V_{0}\) and temperature \(T_{0}\). The left side has an electric heater, which is turned on at very low power to transfer heat \(Q\) to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to \(V_{0} / 2\). Consequently, the gas temperatures on the left and the right sides become \(T_{L}\) and \(T_{R}\), respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.
Question :
The value of is:JEE Advanced 2021 Medium - The area of the region between the curves \(y=\sqrt{\frac{1+\sin x}{\cos x}}\) and \(y=\sqrt{\frac{1-\sin x}{\cos x}}\) bounded by the lines \(x=0\) and \(x=\frac{\pi}{4}\) isJEE Advanced 2008 Hard
- Let be the function defined as if where . Let be a function such that for all . ThenJEE Advanced 2023 Hard
- For the cell , when the concentration of is times the concentration of , the expression for is
Faraday's constant, universal gas constant, temperature,JEE Advanced 2017 Easy