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JEE Advanced · Physics · 5. Laws of Motion

A block of weight 100N is suspended by copper and steel wires of same cross-sectional area 0.5cm2 and, length 3m and 1m, respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are 30o and 60o, respectively. If elongation in copper wire is ΔlC and elongation in steel wire is ΔlS, then the ratio ΔlCΔlS is _____.
[Young's modulus for copper and steel are 1×1011N/m2 and 2×1011N/m2 respectively]

  1. A 6
  2. B 8
  3. C 4
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(D) 2

Step-by-step Solution

Detailed explanation

2.00

Resolving in components
Fx=0
TScos60=TCcos30
TS12=TC32
TS=3TC
ΔlCΔlS=TClCTSlSYS
\(\Rightarrow \frac{\Delta l_C}{\Delta l_S}=\left(\frac{T_C}{T_S}\right)\left(\frac{l_C}{l_S}\right)\left(\frac{Y_S}{Y_C}\right)=\left(\frac{1}{\sqrt{3}}\right)\left(\frac{\sqrt{3}}{1}\right)\) \(\left(\frac{2 \times 10^{11}}{1 \times 10^{11}}\right)=2\)
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