JEE Advanced · Physics · 5. Laws of Motion
A block of weight is suspended by copper and steel wires of same cross-sectional area and, length and respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are and respectively. If elongation in copper wire is and elongation in steel wire is then the ratio is _____.
[Young's modulus for copper and steel are and respectively]

- A 6
- B 8
- C 4
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
2.00

Resolving in components
\(\Rightarrow \frac{\Delta l_C}{\Delta l_S}=\left(\frac{T_C}{T_S}\right)\left(\frac{l_C}{l_S}\right)\left(\frac{Y_S}{Y_C}\right)=\left(\frac{1}{\sqrt{3}}\right)\left(\frac{\sqrt{3}}{1}\right)\) \(\left(\frac{2 \times 10^{11}}{1 \times 10^{11}}\right)=2\)

Resolving in components
\(\Rightarrow \frac{\Delta l_C}{\Delta l_S}=\left(\frac{T_C}{T_S}\right)\left(\frac{l_C}{l_S}\right)\left(\frac{Y_S}{Y_C}\right)=\left(\frac{1}{\sqrt{3}}\right)\left(\frac{\sqrt{3}}{1}\right)\) \(\left(\frac{2 \times 10^{11}}{1 \times 10^{11}}\right)=2\)
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