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JEE Advanced · Mathematics · 9. Straight Lines

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Let \(F_{1}\left(x_{1}, 0\right)\) and \(F_{2}\left(x_{2}, 0\right)\), for \(x_{1}<0\) and \(x_{2}>0\), be the foci of the ellipse \(\frac{x^{2}}{9}+\frac{y^{2}}{8}=1 .\) Suppose a parabola having vertex at the origin and focus at \(F_{2}\) intersects the ellipse at point \(M\) in the first quadrant and at point \(N\) in the fourth quadrant.


Question:

The orthocentre of the triangle \(F_{1} M N\) is

  1. A -910, 0
  2. B 23, 0
  3. C 910, 0
  4. D 23, 6
Verified Solution

Answer & Solution

Correct Answer

(A) -910, 0

Step-by-step Solution

Detailed explanation


x 2 9 + y 2 8 =1
F 1 ( 1,0 ), F 2 ( 1,0 )
Parabola is y 2 =4x
The intersection of ellipse & parabola is M & N
x 2 9 + 4x 8 =1M( 3 2 , 6 )&N( 3 2 , 6 )

Equation of altitude through M :y- 6=526 x-32
Equation of altitude through F1:y=0
Solving, we get orthocentre -910, 0
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