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JEE Advanced · Physics · 1. Math in Physics

Using the expression 2d sin θ=λ, one calculates the values of d by measuring the corresponding angle θ in the range 0 to 90°. The wavelength λ is exactly known and the error in θ is constant for all the values of θ. As θ increases from 0°,

  1. A the absolute error in d remains constant.
  2. B the absolute error in dincreases.
  3. C the fractional error in d remains constant.
  4. D the fractional error in d decreases.
Verified Solution

Answer & Solution

Correct Answer

(D) the fractional error in d decreases.

Step-by-step Solution

Detailed explanation

2d sin θ=λ
d=λ2 sin θ
Differentiate on both the sides,
d=λ2∂ cosec θ
d=λ2-cosec θ cot θθ
d=-λ cos  θsin2 θθ
 θ=increases and λ cos θ2 sin2 θ decreases.
Alternate solution
d=λ2 sin θ
n d=n λ-n 2-n sin θ
Δdd=0-0-1sin θ×cos θΔθ
Fractional error, +d=cot θΔθ
Absolute error, Δd=d cot θΔθ
d2sin θ×cos θsin θ
Δd=cos θsin2 θ
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