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JEE Advanced · Mathematics · 27. Definite Integration

For x, let tan-1x-π2,π2. Then the minimum value of the function f: defined by fx=0xtan-1xet-cost1+t2023dt is

  1. A 5
  2. B 4
  3. C \(0\)
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(C) \(0\)

Step-by-step Solution

Detailed explanation

Given, fx=0xtan-1xet-cost1+t2023dt
From JEE Advanced
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