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JEE Advanced · Chemistry · 4. Chemical Bonding

Among \(H_2, H e_2^{+}, L i_2, B e_2, B_2, C_2, N_2, O_2^{-}\), and \(F_2\), the number of diamagnetic species is -
(Atomic number : \(H=1, H e=2, L i=3, B e=4, B=5,\) \(C=6, N =7, O=8, F=9\) )

  1. A 5
  2. B 10
  3. C 15
  4. D 20
Verified Solution

Answer & Solution

Correct Answer

(A) 5

Step-by-step Solution

Detailed explanation

\(H_2 \Rightarrow \sigma 1 s^2\)(Dia
magnetic)
\(H e_2^{+} \Rightarrow \sigma 1 s^2 \sigma^* 1 s^1\)(Para
magnetic)
\(L i_2 \Rightarrow \sigma 1 s^2 \quad \sigma^* 1 s^2 \quad \sigma 2 s^2\)(Dia
magnetic)
\(B e_2 \Rightarrow \sigma 1 s^2 \quad \sigma^* 1 s^2 \quad \sigma 2 s^2 \quad\)\(\sigma^* 2 s^2\)(Does not exist)
\(B_2 \Rightarrow \sigma 1 s^2 \quad \sigma^* 1 s^2 \quad \sigma 2 s^2 \quad\)\( \sigma^* 2 s^2 \quad \pi 2 p_x^1=\pi 2 p_y^1\)(Para
magnetic)
\(C_2 \Rightarrow \sigma 1 s^2 \quad \sigma^* 1 s^2 \quad \sigma 2 s^2 \quad\)\( \sigma^* 2 s^2 \quad \pi 2 p_x^2=\pi 2 p_y^2\)(Dia
magnetic)
\(N_2 \Rightarrow \sigma 1 s^2 \quad \sigma^* 1 s^2 \quad \sigma 2 s^2 \quad\)\( \sigma^* 2 s^2\quad \pi 2 p_x^2=\pi 2 p_y^2 \quad \sigma 2 p_z^2\)(Dia
magnetic)
\(O_2^{\Theta} \Rightarrow\sigma 1 s^2 \quad \sigma^* 1 s^2 \quad \sigma 2 s^2 \quad\)\(\sigma^* 2 s^2 \quad\sigma 2 p_z^2 \quad \pi 2 p_x^2=\pi 2 p_y^2 \quad\)\(\pi^* 2 p_x^2=\pi^* 2 p_y^1\)(Para
magnetic)
\(F_2 \Rightarrow \sigma 1 s^2 \quad \sigma^* 1 s^2 \quad \sigma 2 s^2 \quad\)\( \sigma^* 2 s^2 \quad\sigma 2 o_z^2 \quad \pi 2 p_x^2=\pi 2 p_y^2 \quad\)\(\pi^* 2 p_x^2=\pi^* 2 p_y^2\)(Dia
magnetic)
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