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JEE Advanced · Mathematics · 25. AOD

A cylindrical container is to be made from certain solid material with the following constraints: It has a fixed inner volume of V mm3, has a 2 mm thick solid wall and is open at the top. The bottom of the container is a solid circular disc of thickness 2mm and is of radius equal to the outer radius of the container.
If the volume of the material used to make the container is minimum when the inner radius of the container is 10mm, then the value of V250π  is

  1. A 9
  2. B 4
  3. C 8
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(B) 4

Step-by-step Solution

Detailed explanation

Volume of material used
V1=πr+22h-πr2h+πr+22.2
=4πhr+1+2πr+22
=4Vr2r+1+2πr+22
h=Vπr2
dV1dr=4V -1r2-2r3+4πr+2
Where r=10,dV1dr=0
4V-1100--21000+48π=0
4V121000=48π
V250π=4
From JEE Advanced
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