JEE Advanced · Physics · 13. Thermodynamics
Paragraph :
\(P_{14-16}\) : Paragraph for Questions Nos. 14 to 16 A fixed thermally conducting cylinder has a radius \(R\) and height \(L_0\). The cylinder is open at its bottom and has a small hole at its top. A piston of mass \(M\) is held at a distance \(L\) from the top surface as shown in the figure. The atmospheric pressure is \(p_0\).

Question :
The piston is now pulled out slowly and held at a distance \(2 L\) from the top. The pressure in the cylinder between its top and the piston will then be
- A \(p_0\)
- B \(\frac{p_0}{2}\)
- C \(\frac{p_0}{2}+\frac{M g}{\pi R^2}\)
- D \(\frac{p_0}{2}-\frac{M g}{\pi R^2}\)
Answer & Solution
Correct Answer
(A) \(p_0\)
Step-by-step Solution
Detailed explanation
Since it is open from top, pressure will be \(p_0\). \(\therefore\) Option (a) is correct.
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