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JEE Advanced · Chemistry · 17. Electrochemistry

The reduction potential E0, in V of MnO4-aq/Mns is
\(\left[\right.\)Given: \(E _{\left( MnO _4^{-}( aq ) / MnO _2(s)\right)}^{ o }=1.68 V ;\) \( E _{\left( MnO _2(s) / Mn ^{2+}( aq )\right)}^{ o }=\) \(1.21 V ; E _{\left( Mn ^{2+}( aq ) / Mn ( s )\right)}^{ o }\) \(=-1.03 V]\)
Truncate/round-off the value to TWO decimal places.

  1. A 0.44
  2. B 0.77
  3. C 0.88
  4. D 0.99
Verified Solution

Answer & Solution

Correct Answer

(B) 0.77

Step-by-step Solution

Detailed explanation

Given (1) MnO4-aq+4H++3eMnO2s+2H2OE°=1.68 V
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