JEE Advanced · Chemistry · 21. p Block (G15-18)

Ozonolysis of ${ClO}_{2}$ produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is ______ .

Verified Solution

Answer & Solution

Correct Answer

(C) 6

Step-by-step Solution

Detailed explanation

Reaction :

{ClO}_{2} + O_{3} \to {ClO}_{3} + O_{2}

{ClO}_{3}

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

The wave function,

ψ_{n, l, m_{l}}

is a mathematical function whose value depends upon spherical polar coordinates

(r, θ, ϕ)

of the electron and characterized by the quantum numbers

n, l

and

m_{l}

. Here

r

is the distance from the nucleus,

θ

is colatitude and

ϕ

is azimuth. In the mathematical functions given in the Table,

Z

is the atomic number and

a_{o}

is Bohr radius

Column 1	Column 2	Column 3
(I) 1s orbital	$\begin{array}{l}\text { (i) } \psi_{ n , 1, m_1} \\ \propto\left(\frac{ Z }{ a _{ o }}\right)^{\frac{3}{2}} e ^{-\left(\frac{ Zr }{ e _{ o }}\right)}\end{array}$	(P)
(II) 2s orbital	(ii) One radial node	(Q) Probability density at the nucleus $\propto \frac{1}{ a _{ o }^3}$.
(III) $2 p _{ z }$ orbital	$\begin{array}{l}\text { (iii) } \psi_{ n }, 1, m_{ l } \\ \propto\left(\frac{ Z }{ a _{ o }}\right)^{\frac{5}{2}} re ^{-\left(\frac{ Zr }{2 a _{ o }}\right)} \cos \theta\end{array}$	(R) Probability density is maximum at the nucleus.
(IV) $3 d_{ z }^2$ orbital	(iv) $x y$-plane is a nodal plane	(S) Energy needed to excite an electron from $n =2$ state to $n =4$ state is $\frac{27}{32}$ times the energy needed to excite are electron from $n =2$ state to $n =6$ state.

For the given orbital in column 1, the only correct combination for any hydrogen-like species is

JEE Advanced 2017 Hard

Paragraph:
$RCONH _2$ is converted into $RNH _2$ by means of Hofmann bromamide degradation.

In this reaction, $R \mathrm{CONHBr}$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.
Question:
Which is the rate determining step in Hofmann bromamide degradation?

JEE Advanced 2006 Hard

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Ozonolysis of ClO2 produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is ______ .

Step-by-step Solution

Ozonolysis of ${ClO}_{2}$ produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is ______ .