JEE Advanced · Chemistry · 13. GOC
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The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by \(s\)-character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below:
Question:
Correct match of the \(\mathbf{C}-\mathbf{H}\) bonds (shown in bold) in Column \(\mathbf{J}\) with their BDE in Column \(\mathbf{K}\) is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
Relative stability of radicals : \(\underset{( sp )}{\dot{ C }} \equiv CH >\underset{\left( sp ^2\right)}{\dot{ C }} H = CH _2>\)\(\underset{\left( sp ^3\right)(\text { Resonance stabilized })}{\dot{ C } H _2- Ph }>\underset{\left( sp ^3\right)}{\dot{ C } H }\left( CH _3\right)_2\) So,
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