JEE Advanced · Chemistry · 1. Mole Concept

Reaction of $\mathbf{x}$ g of $\mathrm{Sn}$ with $\mathrm{HCl}$ quantitatively produced a salt. Entire amount of the salt reacted with $\mathbf{y} g$ of nitrobenzene in the presence of required amount of $\mathrm{HCl}$ to produce $1.29 \mathrm{~g}$ of an organic salt (quantitatively).
(Use Molar masses (in $\mathrm{g} \mathrm{mol}^{-1}$ ) of $\mathrm{H}, \mathrm{C}, \mathrm{N}, \mathrm{O}, \mathrm{Cl}$ and $\mathrm{Sn}$ as $1,12,14,16,35$ and 119 , respectively).
The value of $x$ is _______ .

A 0.5
B 0.314
C 3.57
D 2.34

Verified Solution

Answer & Solution

Correct Answer

(C) 3.57

Step-by-step Solution

Detailed explanation

Mass of salt produced

= 1.29 g

Moles of salt produced

= \frac{1 .29}{129} = 0 .01 mole

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match the compounds in List-I with the appropriate observations in List-II and choose the correct option.

List - I	List - II
(P)	(1) Reaction with phenyl diazonium salt gives #ff0 dye.
(Q)	(2) Reaction with ninhydrin gives purple color and it also reacts with $FeCl _3$ to give violet color.
(R)	(3) Reaction with glucose will give corresponding hydrazone.
(S)	(4) Lassiagne extract of the compound treated with dilute HCl followed by addition of aqueous $FeCl _3$ gives blood red color.
	(5) After complete hydrolysis,it will give ninhydrin test and it DOES NOT give positive phthalein dye test.

JEE Advanced 2025 Medium

A compound $H_{2} X$ with molar weight of 80g is dissolved in a solvent having density of $0.4 g m l^{- 1}$ . Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is

JEE Advanced 2014 Medium

The wave function, $\psi_{ n , 1, m_{ l }}$ is a mathematical function whose value depends upon spherical polar coordinates $( r , \theta, \phi)$ of the electron and characterized by the quantum numbers $n , 1$ and $m _{ l }$. Here $r$ is the distance from the nucleus, $\theta$ is colatitude and $\phi$ is azimuth. In the mathematical functions given in the Table, Z is the atomic number and $a_0$ is Bohr radius

Column 1	Column 2	Column 3
(I) 1s orbital	$\text {(i) } \psi_{ n , 1, m_1}$ $\propto\left(\frac{ Z }{ a _{ o }}\right)^{\frac{3}{2}} e ^{-\left(\frac{ Zr }{ e _{ o }}\right)}$	(P)
(II) 2s orbital	(ii) One radial node	(Q) Probability density at the nucleus $\propto \frac{1}{ a _{ o }^3}$.
(III) $2 p _{ z }$ orbital	$\text {(iii) } \psi_{ n }, 1, m_{ l }$ $\propto\left(\frac{ Z }{ a _{ o }}\right)^{\frac{5}{2}} re ^{-\left(\frac{ Zr }{2 a _{ o }}\right)} \cos \theta$	(R) Probability density is maximum at the nucleus.
(IV) $3 d_{ z }^2$ orbital	(iv) $x y$-plane is a nodal plane	(S) Energy needed to excite an electron from $n =2$ state to $n =4$ state is $\frac{27}{32}$ times the energy needed to excite are electron from $n =2$ state to $n =6$ state.

For $\text{He} ^{+}$ion, the only incorrect combination

JEE Advanced 2017 Hard

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