JEE Advanced · Chemistry · 4. Chemical Bonding
The spin only magnetic moment value (in Bohr magneton units) of \(\mathrm{Cr}(\mathrm{CO})_6\) is
- A \(0\)
- B \(2.84\)
- C \(4.90\)
- D \(5.92\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CO}\) is a strong ligand, all the six electron of the valence shell of \(\mathrm{Cr}\) is paired and spin only magnetic moment \(=0\).
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