JEE Advanced · Chemistry · 24. Haloalkanes & Haloarenes
LIST-I contains reactions and LIST-II contains major products
| List - I | List - II |
(A) | (P)  |
(B)  | (Q)  |
(C)  | (R)  |
(D)  | (S)  |
(T)  |
- A a-s,t;b-s;c-q,r;d-q,r,s;
- B a-r,s,t;b-r;c-s,t;d-s,t;
- C a-p,s;b-q;c-s;d-r;
- D a-q;b-s,t;c-r;d-t;
Answer & Solution
Correct Answer
(C) a-p,s;b-q;c-s;d-r;
Step-by-step Solution
Detailed explanation
Bulky base is present, it will abstract proton, hence will undergo E2 reaction
Hydrogen ion will protonate the oxygen of methoxy group and make it a good leaving group, hence methanol and t-butyl bromide is formed.
Methoxy group will abstract proton. E2 elimination occur
It will undergo mechanism.
Hydrogen ion will protonate the oxygen of methoxy group and make it a good leaving group, hence methanol and t-butyl bromide is formed.
Methoxy group will abstract proton. E2 elimination occur
It will undergo mechanism.
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