JEE Advanced · Chemistry · 4. Chemical Bonding
Among the following, the paramagnetic compound is
- A \(\mathrm{Na}_2 \mathrm{O}_2\)
- B \(\mathrm{O}_3\)
- C \(\mathrm{N}_2 \mathrm{O}\)
- D \(\mathrm{KO}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{KO}_2\)
Step-by-step Solution
Detailed explanation
For \(\mathrm{KO}_2, \mathrm{O}_2^{-}\)has unpaired \(e^{-} \Rightarrow\) paramagnetic
\(\mathrm{O}_2^{-} \text {: Total } e^{-} s=16+1=17 \)
\( \sigma 1 s^2, \sigma^* 1 s^2 \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p_z^2 \pi 2 p_x^{1+1} \)
\( =\pi 2 p_y^{1+1}, \pi^* 2 p_x^{1+1}=\pi 2 p_y^1\)
\(\mathrm{O}_2^{-} \text {: Total } e^{-} s=16+1=17 \)
\( \sigma 1 s^2, \sigma^* 1 s^2 \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p_z^2 \pi 2 p_x^{1+1} \)
\( =\pi 2 p_y^{1+1}, \pi^* 2 p_x^{1+1}=\pi 2 p_y^1\)
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