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JEE Advanced · Chemistry · 4. Chemical Bonding

Among the following, the paramagnetic compound is

  1. A \(\mathrm{Na}_2 \mathrm{O}_2\)
  2. B \(\mathrm{O}_3\)
  3. C \(\mathrm{N}_2 \mathrm{O}\)
  4. D \(\mathrm{KO}_2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{KO}_2\)

Step-by-step Solution

Detailed explanation

For \(\mathrm{KO}_2, \mathrm{O}_2^{-}\)has unpaired \(e^{-} \Rightarrow\) paramagnetic
\(\mathrm{O}_2^{-} \text {: Total } e^{-} s=16+1=17 \)
\( \sigma 1 s^2, \sigma^* 1 s^2 \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p_z^2 \pi 2 p_x^{1+1} \)
\( =\pi 2 p_y^{1+1}, \pi^* 2 p_x^{1+1}=\pi 2 p_y^1\)
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