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JEE Advanced · Chemistry · 31. Practical Chemistry

The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is
List - IList - II
(P) Passing \(H _2 S\) in the presence of \(NH _4 OH\)(1) \(Cu ^{2+}\)
(Q) \(\left( NH _4\right)_2 CO _3\) in the presence of \(NH _4 OH\)(2) \(Al ^{3+}\)
(R) \(NH _4 OH\) in the presence of \(NH _4 Cl\)(3) \(Mn ^{2+}\)
(S) Passing \(H _2 S\) in the presence of dilute HCl(4) \(Ba ^{2+}\)
(5) \(Mg ^{2+}\)

  1. A \(\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 1\)
  2. B \(\mathrm{P} \rightarrow 4 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 3 ; \mathrm{S} \rightarrow 1\)
  3. C \(\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 1 ; \mathrm{S} \rightarrow 5\)
  4. D \(\mathrm{P} \rightarrow 5 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 4\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 1\)

Step-by-step Solution

Detailed explanation

\(\mathrm{Mn}^{+2} \xrightarrow{\mathrm{H}_2 \mathrm{~S}+\mathrm{NH}_4 \mathrm{OH}} \underset{\text { Pink/buff ppt. }}{\mathrm{MnS} \downarrow}\)
\(\mathrm{Ba}^{+2} \xrightarrow{\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3+\mathrm{NH}_4 \mathrm{OH}} \underset{\text { White ppt. }}{\mathrm{BaCO}_3 \downarrow}\)
\(\mathrm{Al}^{+3} \xrightarrow{\mathrm{NH}_4 \mathrm{Cl}+\mathrm{NH}_4 \mathrm{OH}} \underset{\text { White ppt. }}{\mathrm{Al}(\mathrm{OH})_3 \downarrow}\)
\(\mathrm{Cu}^{+2} \xrightarrow{\mathrm{H}_2 \mathrm{~S}+\mathrm{HCl} \text { (dil.) }} \underset{\text { Black ppt. }}{\mathrm{CuS} \downarrow}\)
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