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JEE Advanced · Chemistry · 23. Coordination Compounds

Both \(\left[\mathrm{Ni}(\mathrm{CO})_4\right]\) and \(\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}\) are diamagnetic. The hybridisations of nickel in these complexes, respectively, are

  1. A \(s p^3, s p^3\)
  2. B \(s p^3, d s p^2\)
  3. C \(d s p^2, s p^3\)
  4. D \(d s p^2, d s p^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(s p^3, d s p^2\)

Step-by-step Solution

Detailed explanation

In \(\left[\mathrm{Ni}(\mathrm{CO})_4\right]\), the oxidation state of \(\mathrm{Ni}\) is zero \((0)\).
\(\mathrm{Ni}(28)[\mathrm{Ar}] 4 \mathrm{~s}^2, 3 d^8\)


\(\mathrm{CO} \text { is a strong ligand, causes coupling, thus }\)


In \(\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}\), the oxidation state of \(\mathrm{Ni}\) is \(+2\) \(\mathrm{Ni}^{2+}=[\mathrm{Ar}] 3 d^8, 4 s^0\)

\(\mathrm{CN}^{-} \text {is strong ligand causes coupling. }\)
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