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JEE Advanced · Chemistry · 8. Ionic Equilibrium

A solution is prepared by mixing 0.01mol each of H2CO3,NaHCO3,Na2CO3, and NaOH in \(100 \mathrm{~mL}\) of water. pH of the resulting solution is
[Given: pKa1 and pKa2 of H2CO3 are 6.37 and 10.32, respectively. log2=0.30]

  1. A 10.04
  2. B 10.24
  3. C 10.02
  4. D 10.54
Verified Solution

Answer & Solution

Correct Answer

(C) 10.02

Step-by-step Solution

Detailed explanation

First acid base reaction between H2CO3 and NaOH takes place. H2CO30.01mole+NaOH0.01moleNaHCO3-0.01mole+H2O
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