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GUJCET · Physics · Ray Optics and Optical Instruments
A ray of light passes from a medium \(A\) having refractive index 1.6 to the medium \(B\) having refractive index 1.5 . The value of critical angle of medium \(A\) is ________ .
- A \(\sin ^{-1} \sqrt{\frac{16}{15}}\)
- B \(\sin ^{-1}\left(\frac{16}{15}\right)\)
- C \(\sin ^{-1}\left(\frac{1}{2}\right)\)
- D \(\sin ^{-1}\left(\frac{15}{16}\right)\)
Answer & Solution
Correct Answer
(D) \(\sin ^{-1}\left(\frac{15}{16}\right)\)
Step-by-step Solution
Detailed explanation
(D) \(\sin ^{-1}\left(\frac{15}{16}\right)\)
\(
\begin{aligned}
& & \sin i_{c} & =\frac{n_{2}}{n_{1}} \\
& \therefore & \sin i_{c} & =\frac{1.5}{1.6} \\
& \therefore & i_{c} & =\sin ^{-1}\left(\frac{1.5}{1.6}\right) \\
& \therefore & i_{c} & =\sin ^{-1}\left(\frac{15}{16}\right)
\end{aligned}
\)
\(
\begin{aligned}
& & \sin i_{c} & =\frac{n_{2}}{n_{1}} \\
& \therefore & \sin i_{c} & =\frac{1.5}{1.6} \\
& \therefore & i_{c} & =\sin ^{-1}\left(\frac{1.5}{1.6}\right) \\
& \therefore & i_{c} & =\sin ^{-1}\left(\frac{15}{16}\right)
\end{aligned}
\)
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