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GUJCET · Physics · Current Electricity
A metal rod of length 10 cm and a rectangular cross section of \(1 cm \times \frac{1}{2} cm\) is connected to a battery across opposite faces. The resistance will be _________.
- A Maximum when the battery is connected across \(10 cm \times 1 cm\).
- B Maximum when the battery is connected across \(1 cm \times \frac{1}{2} cm\) faces.
- C Maximum when the battery is connected across \(10 cm \times \frac{1}{2} cm\).
- D Same irrespective of three faces.
Answer & Solution
Correct Answer
(B) Maximum when the battery is connected across \(1 cm \times \frac{1}{2} cm\) faces.
Step-by-step Solution
Detailed explanation
(B)
length of metal rod \(l=10 cm\)
Area of rectangular cross section \(A=1 cm \times \frac{1}{2} cm\)
Resistance of wire of resistivity \(\rho\) is given by \(R =\frac{\rho l}{A}\)
Resistance of the wire will be maximum when length of the wire is maximum and area is minimum.
length of metal rod \(l=10 cm\)
Area of rectangular cross section \(A=1 cm \times \frac{1}{2} cm\)
Resistance of wire of resistivity \(\rho\) is given by \(R =\frac{\rho l}{A}\)
Resistance of the wire will be maximum when length of the wire is maximum and area is minimum.
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