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GUJCET · Physics · Electrostatic Potential and Capacitance
The unit of polarizability of the molecule is ________.
- A \(C ^2 m^1 N^{-1}\)
- B \(C ^{-2} m^{-1} N^1\)
- C \(C ^{+2} m^{-1} N^{-1}\)
- D \(C ^{-2} m^1 N^{-1}\)
Answer & Solution
Correct Answer
(A) \(C ^2 m^1 N^{-1}\)
Step-by-step Solution
Detailed explanation
(A)
\(\vec{p} \quad=\alpha \overrightarrow{E_0}\)
where \(\alpha=\) polarizability of molecule
\(\therefore \alpha=\frac{\vec{p}}{\overrightarrow{ E _0}}\)
\(=\frac{ C -m}{\frac{N}{ C }}=\frac{ C ^2-m}{N}\)
\(\vec{p} \quad=\alpha \overrightarrow{E_0}\)
where \(\alpha=\) polarizability of molecule
\(\therefore \alpha=\frac{\vec{p}}{\overrightarrow{ E _0}}\)
\(=\frac{ C -m}{\frac{N}{ C }}=\frac{ C ^2-m}{N}\)
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