At \(27^{\circ} C\) temperature, time required for \(75 \%\) completion of a first order reaction is 20 seconds. What will be its rate constant?

A \(0.693 sec ^{-1}\).
B \(0.0693 sec ^{-1}\)
C \(0.693 sec ^{-1}\) mole \({ }^{-1}\) lt
D \(0.0693 sec ^{-1} mole^{-1}\) It

Verified Solution

Answer & Solution

Correct Answer

(B) \(0.0693 sec ^{-1}\)

Step-by-step Solution

Detailed explanation

B
For 1st order reaction;

\(\begin{array}{l}
K t=\ln \left(\frac{A_0}{A_t}\right) \\
K(20)=\ln \left(\frac{A_0}{0.25 A_0}\right) \\
K(20)=\ln (4) \\
K=\frac{2 \ln 2}{20}=\frac{0.693}{10}=0.0693 s^{-1}
\end{array}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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