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GUJCET · Physics · Current Electricity

At room temperature \(\left(27^{\circ} C \right)\) the resistance of a heating element is \(100 \Omega\). What is the temperature of the element if the resistance is found to be \(137 \Omega\), given that the temperature coefficient of the material of the resistor is \(1.35 \times 10^{-40} C ^{-1}\).

  1. A \(2767^{\circ} C\)
  2. B \(1227^{\circ} C\)
  3. C \(1027^{\circ} C\)
  4. D \(2327^{\circ} C\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2767^{\circ} C\)

Step-by-step Solution

Detailed explanation

(A)
\(\begin{array}{l}
R_\theta=R_0\left[1+\alpha\left(\theta-\theta_0\right)\right] \\
137=100[1+1.35 \left.\times 10^{-4}(\theta-27)\right] \\
\therefore 1.37=1+1.35 \times 10^{-4}(\theta-27) \\
\therefore 0.37=1.35 \times 10^{-4}(\theta-27) \\
\therefore \frac{0.37}{1.35 \times 10^{-4}}=\theta-27 \\
\therefore 2740.74=\theta-27 \\
\therefore \theta \approx 2767^{\circ} C
\end{array}\)