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GUJCET · Physics · Ray Optics and Optical Instruments
Glass prism having a refractive index \(\mu\), placed in a air, for that angle of minimum deviation of prism is same as angle of prism. Then what is value of angle of prism?
- A \(\cos ^{-1}(\mu)\)
- B \(\cos ^{-1}\left(\frac{\mu}{2}\right)\)
- C \(2 \cos ^{-1}(\mu)\)
- D \(2 \cos ^{-1}\left(\frac{\mu}{2}\right)\)
Answer & Solution
Correct Answer
(D) \(2 \cos ^{-1}\left(\frac{\mu}{2}\right)\)
Step-by-step Solution
Detailed explanation
(D) \(2 \cos ^{-1}\left(\frac{\mu}{2}\right)\)
\(\mu=\frac{\sin \left(\frac{\mathrm{A}+\mathrm{D}_{m}}{2}\right)}{\sin \frac{\mathrm{A}}{2}}\)
\(\therefore \quad \mu=\frac{\sin \left(\frac{\mathrm{A}+\mathrm{A}}{2}\right)}{\sin \frac{\mathrm{A}}{2}}\)
\(\therefore \mu=\frac{\sin \mathrm{A}}{\sin \frac{\mathrm{A}}{2}}\)
\(\therefore \quad \mu=\frac{2 \sin \frac{\mathrm{~A}}{2} \cos \frac{\mathrm{~A}}{2}}{\sin \frac{\mathrm{~A}}{2}}\)
\(\therefore \quad \frac{\mu}{2}=\cos \frac{\mathrm{A}}{2}\)
\(\therefore \frac{\mathrm{A}}{2}=\cos ^{-1}\left(\frac{\mu}{2}\right)\)
\(\therefore \quad \mathrm{A}=2 \cos ^{-1}\left(\frac{\mu}{2}\right)\)
\(\mu=\frac{\sin \left(\frac{\mathrm{A}+\mathrm{D}_{m}}{2}\right)}{\sin \frac{\mathrm{A}}{2}}\)
\(\therefore \quad \mu=\frac{\sin \left(\frac{\mathrm{A}+\mathrm{A}}{2}\right)}{\sin \frac{\mathrm{A}}{2}}\)
\(\therefore \mu=\frac{\sin \mathrm{A}}{\sin \frac{\mathrm{A}}{2}}\)
\(\therefore \quad \mu=\frac{2 \sin \frac{\mathrm{~A}}{2} \cos \frac{\mathrm{~A}}{2}}{\sin \frac{\mathrm{~A}}{2}}\)
\(\therefore \quad \frac{\mu}{2}=\cos \frac{\mathrm{A}}{2}\)
\(\therefore \frac{\mathrm{A}}{2}=\cos ^{-1}\left(\frac{\mu}{2}\right)\)
\(\therefore \quad \mathrm{A}=2 \cos ^{-1}\left(\frac{\mu}{2}\right)\)
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