AP EAMCET · PHYSICS · Electromagnetic Induction
A metal loop of area \(10 \mathrm{~cm}^2\) is placed in a region such that its area vector points along \(\hat{\mathrm{k}}\). The region contains a uniform magnetic field of magnitude \(1.73 \mathrm{~T}\) that points in the direction \(\hat{i}+\hat{j}+\hat{k}\). When the magnetic field is switched off, the field decreases to zero at a steady rate in \(10 \mathrm{~s}\), then the magnitude of emf induced in the loop is
- A \(0.10 \mathrm{mV}\)
- B \(0.17 \mathrm{mV}\)
- C \(1 \mathrm{mV}\)
- D \(1.7 \mathrm{mV}\)
Answer & Solution
Correct Answer
(A) \(0.10 \mathrm{mV}\)
Step-by-step Solution
Detailed explanation
We have \(\mathrm{e}=-\frac{\Delta \phi}{\Delta \mathrm{t}}\) \(\Rightarrow \quad \mathrm{e}=\frac{-\left(\phi_{\mathrm{f}}-\phi_{\mathrm{i}}\right)}{\Delta \mathrm{t}}=\frac{\phi_{\mathrm{i}}-\phi_{\mathrm{f}}}{\Delta \mathrm{t}}\)…
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