AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A bullet of mass \(10 \mathrm{~g}\) pierces through a plate \(A\) of mass \(500 \mathrm{~g}\) and then gets embedded into a second plate \(B\) of mass \(1.49 \mathrm{~kg}\) as shown in the figure. Initially, the two plates \(A\) and \(B\) are at rest and move with same velocity after collision. The percentage loss in the initial kinetic energy of the bullet, when it is between the plates \(A\) and \(B\) is _______
(Neglect any loss of material of the plates during the collision)
[QUESTION]
- A 25
- B 56.25
- C 43.75
- D 75
Answer & Solution
Correct Answer
(C) 43.75
Step-by-step Solution
Detailed explanation
Let \(v_1\) be the initial velocity of bullet and \(v_2\) be the velocity with which each plate moves. So, applying law of conservation of momentum, \( \begin{aligned} & m v_1=M_1 v_2+\left(M_2+m\right) v_2 \\ & 0.01 v_1=0.5 v_2+(1.49+0.01) v_2 \end{aligned} \)…
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