AP EAMCET · Maths · Basic of Mathematics
The set \(\left\{x \in \mathbb{R}: 4+11 x-3 x^2>0\right\}\) is the interval
- A \(\left(-\frac{1}{3}, 4\right)\)
- B \((-, 4)\)
- C \(\left(-4, \frac{1}{3}\right)\)
- D \(\left(-4, \frac{-1}{3}\right)\)
Answer & Solution
Correct Answer
(A) \(\left(-\frac{1}{3}, 4\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {Given: }\left\{x \in R: 4+11 x-3 x^2>0\right\} \\ & \because 4+11 x-3 x^2>0 \\ & \Rightarrow-(x-4)(3 x-1)>0 \\ & \Rightarrow(x-4)(3 x-1) \(\therefore x \in\left(-\frac{1}{3}, 4\right)\)
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