AP EAMCET · PHYSICS · Waves and Sound
A source \(S\) emitting sound of frequency \(288 \mathrm{~Hz}\) is fixed on block \(B\) which is attached to the free end of a spring \(S_2\) and an observer \(O\) is on block \(A\) which is attached to the free end of spring \(S_1\) as shown in the figure. The blocks \(A\) and \(B\) are simultaneously displaced towards each other through a distance of \(0.5 \mathrm{~m}\) and then left to oscillate. If the angular velocity of each blocks is \(40 \mathrm{rad} \mathrm{s}^{-1}\), then the maximum frequency observed by the observer is (speed of sound in air is \(340 \mathrm{~ms}^{-1}\) )
- A 288 Hz
- B 310 Hz
- C 324 Hz
- D 256 Hz
Answer & Solution
Correct Answer
(C) 324 Hz
Step-by-step Solution
Detailed explanation
Frequency is maximum, when both \(O\) and ' \(S\) ' are moving towards each other with maximum speeds. Now, maximum speed of \(O=\) maximum speed of \(S\) [and these two occur together]. \[ =v_m=a \omega=0.5 \times 40=20 \mathrm{~ms}^{-1} \] So, maximum frequency…
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