AP EAMCET · PHYSICS · Thermal Properties of Matter
The temperature of water of mass 100 g is rasied from \(24^{\circ} \mathrm{C}\) to \(90^{\circ} \mathrm{C}\) by adding steam to it. The mass of the steam added is
(Latent heat of steam \(=540 \mathrm{cal} \mathrm{g}^{-1}\) and specific heat capacity of water \(=1 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\) )
- A 10 g
- B 12 g
- C 8 g
- D 16 g
Answer & Solution
Correct Answer
(B) 12 g
Step-by-step Solution
Detailed explanation
\(m_{\mathrm{w}} c_{\mathrm{w}} \Delta T_{\mathrm{w}} = m_{\mathrm{s}} (L_{\mathrm{s}} + c_{\mathrm{w}} \Delta T_{\mathrm{s}})\)…
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