AP EAMCET · PHYSICS · Units and Dimensions
The number of significant figures in the simplification of \(\frac{0.501}{0.05}(0.312-0.03)\) is
- A 1
- B 3
- C 2
- D 5
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
\(0.312 - 0.03 = 0.282\) Significant figures for this result (due to 2 decimal places in \(0.03\)): 2 \(\frac{0.501}{0.05} = 10.02\) Significant figures for this result (due to 1 significant figure in \(0.05\)): 1 \(10.02 \times 0.282 = 2.82564\) For the product, the number of…
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