AP EAMCET · Maths · Circle
The line \(x+y+2=0\) intersect the circle \(x^2+y^2+4 x-\) \(4 y-4=0\) in two points \(A\) and \(B\). Let \(S \equiv x^2+y^2+2 g x+\) \(2 \mathrm{fy}+\mathrm{c}=0\) be a different circle passing through the points \(A\) and \(B\). If the distance of the centre of \(S=0\) from \(A B\) is \(\sqrt{2}\), then \(\mathrm{g}+\mathrm{f}+\mathrm{c}=\)
- A \(12\)
- B \(8\)
- C \(6\)
- D \(0\)
Answer & Solution
Correct Answer
(B) \(8\)
Step-by-step Solution
Detailed explanation
Equation of circle(s) passing through intersection of line and circle is \(x^2+y^2+4 x-4 y-4+\lambda(x+y+2)=0\) \(x^2+y^2+(4+\lambda) x+(\lambda-4) y+(2 \lambda-4)=0\) But \(x^2+y^2+2 g x+2 f y+c=0\) (Given)…
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