AP EAMCET · Maths · Circle
If the acute angle between the pair of tangents drawn from the origin to the circle \(x^2+y^2-4 x-8 y+4=0\) is \(\alpha\), then \(\tan \alpha=\)
- A \(3 / 5\)
- B \(3 / 5\)
- C \(4 / 3\)
- D \(4 / 5\)
Answer & Solution
Correct Answer
(C) \(4 / 3\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {} \because \mathrm{x}^2+\mathrm{y}^2-4 \mathrm{x}-8 \mathrm{y}+4=0 \\ & C \equiv \mathrm{x}^2+\mathrm{y}^2\left(-\mathrm{g}_1-\mathrm{f}\right)=(2,4) \mathrm{r}=\sqrt{4+16-4}=4\end{aligned}\) Equation of pair of tangents is…
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