AP EAMCET · Maths · Complex Number
If \(\omega\) is a complex cube root of unity, then \(\sum_{r=1}^9 r(r+1-\omega)\left(r+1-\omega^2\right)=\)
- A 5025
- B 4020
- C 2016
- D 3015
Answer & Solution
Correct Answer
(D) 3015
Step-by-step Solution
Detailed explanation
As, \(\omega\) is complex cube root of unity, then \(\begin{aligned} 1+\omega+\omega^2 & =0 \\ \text{and } \omega^3 & =1 \quad\ldots (i) \end{aligned}\)…
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