AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
Two bodies of mass \(4 \mathrm{~kg}\) and \(5 \mathrm{~kg}\) are moving along east and north directions with velocities \(5 \mathrm{~m} / \mathrm{s}\) and \(3 \mathrm{~m} / \mathrm{s}\) respectively. Magnitude of the velocity of centre of mass of the system is
- A \(\frac{25}{9} \mathrm{~m} / \mathrm{s}\)
- B \(\frac{9}{25} \mathrm{~m} / \mathrm{s}\)
- C \(\frac{41}{9} \mathrm{~m} / \mathrm{s}\)
- D \(\frac{16}{9} \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(\frac{25}{9} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Velocity of centre of mass is \[ \mathbf{v}_{\mathrm{CM}}=\frac{m_1 \mathbf{v}_1+m_2 \mathbf{v}_2}{m_1+m_2} \] Given, \(m_1=4 \mathrm{~kg}, m_2=5 \mathrm{~kg}, v_1=5 \hat{\mathbf{j}} \mathrm{m} / \mathrm{s}\)…
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