AP EAMCET · Maths · Probability
The probability of a non-leap year having 53 Mondays is .........
- A \(\frac{2}{7}\)
- B \(\frac{1}{7}\)
- C \(\frac{5}{7}\)
- D \(\frac{6}{7}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{7}\)
Step-by-step Solution
Detailed explanation
Number of days in non Leap year \(=365\) \[ \begin{aligned} & =52 \times 7+1 \\ & =52 \text { weeks }+1 \text { day } \end{aligned} \] The one additional day may be any one of the day…
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