AP EAMCET · Maths · Straight Lines
If the line \(2 x-3 y+5=0\) is the perpendicular bisector of the line segment joining \((1,-2)\) and \((\alpha, \beta)\), then \(\alpha+\beta=\)
- A 7
- B 1
- C -1
- D -7
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
\(2 x-3 y+5=0\) is perpendicular bisector then mid point of \(A(1,-2)\) and \((\alpha, \beta)\) lines on the line segment AB \(\mathrm{AB}=\left(\frac{\alpha+1}{2}, \frac{\beta-2}{2}\right) \Rightarrow 2\left(\frac{\alpha+1}{2}\right)-3\left(\frac{\beta-2}{2}\right)+5=0\)…
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