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JEE Mains · Maths · STD 11 - 12. limits

यदि \(\lim _{x \rightarrow 1} \frac{\sin \left(3 x^2-4 x+1\right)-x^2+1}{2 x^3-7 x^2+a x+b}=-2\) है,तो \(( a - b )\) का मान है

  1. A
    \(17\)
  2. B \(10\)
  3. C \(11\)
  4. D \(18\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(11\)

Step-by-step Solution

Detailed explanation

\(\lim \limits_{x \rightarrow 1} \frac{\sin \left(3 x^{2}-4 x+1\right)-x^{2}+1}{2 x^{3}-7 x^{2}+a x+b}=-2\) For finite limit \(a+b-5=0\)...............\((1)\) Apply \(L'H \)rule…
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