JEE Mains · Maths · STD 11 - 12. limits
If \(\lim\limits _{x \rightarrow 1} \frac{\sin \left(3 x^{2}-4 x+1\right)-x^{2}+1}{2 x^{3}-7 x^{2}+a x+b}=-2\), then the value of \((a-b)\) is equal to
- A
\(17\)
- B \(10\)
- C \(11\)
- D \(18\)
Answer & Solution
Correct Answer
(C) \(11\)
Step-by-step Solution
Detailed explanation
\(\lim \limits_{x \rightarrow 1} \frac{\sin \left(3 x^{2}-4 x+1\right)-x^{2}+1}{2 x^{3}-7 x^{2}+a x+b}=-2\) For finite limit \(a+b-5=0\)...............\((1)\) Apply \(L'H \)rule…
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