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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

यदि रेखा \(ax + y = c\), दोनों वक्रों \(x ^{2}+ y ^{2}=1\) तथा \(y ^{2}=4 \sqrt{2} x\) को स्पर्श करती है, तो \(| c |\) बराबर है

  1. A \(\frac {1}{\sqrt 2}\)
  2. B \(\sqrt 2\)
  3. C \(\frac {1}{2}\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt 2\)

Step-by-step Solution

Detailed explanation

Tangent to \({y^2} = 4\sqrt 2 x\) is \(y = mx + \frac{{\sqrt 2 }}{m}\) it is also tangent to \({x^2} + {y^2} = 1\) \( \Rightarrow \left| {\frac{{\sqrt 2 /m}}{{\sqrt {1 + {m^2}} }}} \right| = 1 \Rightarrow m = \pm 1\) \( \Rightarrow \) Tnagent will be \(y = x + \sqrt 2 \) or…
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