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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

यदि फलन \(f ( x )=\left\{\begin{array}{cc}\frac{1}{ x } \log _{ e }\left(\frac{1+\frac{ x }{ a }}{1-\frac{ x }{ b }}\right) & , \quad x <0 \\ k & , \quad x =0 \\ \frac{\cos ^{2} x -\sin ^{2} x -1}{\sqrt{ x ^{2}+1}-1}, & x >0\end{array}\right.\) \(x =0\) पर संतत है, तो \(\frac{1}{ a }+\frac{1}{ b }+\frac{4}{ k }\) बराबर है

  1. A \(-5\)
  2. B \(5\)
  3. C \(-4\)
  4. D \(4\)
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Answer & Solution

Correct Answer

(A) \(-5\)

Step-by-step Solution

Detailed explanation

If \(f(\mathrm{x})\) is continuous at \(\mathrm{x}=0, \mathrm{RHL}=\mathrm{LHL}=f(0)\) \(\lim _{x \rightarrow 0^{+}} f(x)=\lim _{x \rightarrow 0^{+}} \frac{\cos ^{2} x-\sin ^{2} x-1}{\sqrt{x^{2}+1}-1} \cdot \frac{\sqrt{x^{2}+1}+1}{\sqrt{x^{2}+1}+1}\) (Rationalisation)…
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