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JEE Mains · Maths · STD 12 - 13. probability

यदि \(A\) तथा \(B\) दो ऐसी घटनाएँ हैं कि \(P(A)=2 / 5\) तथा \(P ( A \cap B )=3 / 20\) है, तो प्रतिबंधित प्रायिकता \(P \left( A \mid\left( A ^{\prime} \cup B ^{\prime}\right)\right)\), जहाँ \(A ^{\prime}, A\) के पूरक समुच्चय को निर्दिष्ट करता है, बराबर है

  1. A \(11/20\)
  2. B \(5/17\)
  3. C \(8/17\)
  4. D \(1/4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(5/17\)

Step-by-step Solution

Detailed explanation

\(P(A)=\frac{2}{5}=\frac{8}{20} ; P(A \cap B)=\frac{3}{20}\) \(P(\overline{A \cap B})=1-\frac{3}{20}\) \(\Rightarrow \quad P(\bar{A} \cup \bar{B})=\frac{17}{20}\) \({A \cap\left(A^{\prime} \cup B^{\prime}\right)} \) \({=A-(A \cap B)} \) \(\therefore \)…
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