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JEE Mains · Maths · STD 12 - 7.2 definite integral

यदि \(24 \int_0^{\frac{\pi}{4}}\left(\sin \left|4 x-\frac{\pi}{12}\right|+[2 \sin x]\right) \mathrm{d} x=2 \pi+\alpha\), जहाँ \([\cdot]\) महत्तम पूर्णांक फलन को निरूपित करता है, तो \(\alpha\) = ___

  1. A 10
  2. B 12
  3. C 14
  4. D 16
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Answer & Solution

Correct Answer

(B) 12

Step-by-step Solution

Detailed explanation

Let \(I=24 \int_0^{\frac{\pi}{2}}\left(\sin \left|4 x-\frac{\pi}{2}\right|+[2 \sin x]\right) d x\) ...(i) Now \(\left|4 x-\frac{\pi}{12}\right|= \begin{cases}-4 x+\frac{\pi}{12} & ; x < \frac{\pi}{48} \\ 4 x-\frac{\pi}{12} & ; \quad x \geq \frac{\pi}{48}\end{cases}\)…
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