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JEE Mains · Maths · STD 11 - 8. sequence and series

यदि \(\left.\left(1+\frac{2}{3}+\frac{6}{3^{2}}+\frac{10}{3^{3}}+\ldots \ldots \infty \text { तक }\right)^{\log _{10251}\left(\frac{1}{3}+\frac{1}{j^{2}}+\frac{1}{j^{3}}+\ldots \ldots \infty\right. \text { तक }}\right)\) का मान \(l\) है, तो \(l^{2}\) बराबर है ................ |

  1. A \(2\)
  2. B \(3\)
  3. C \(4\)
  4. D \(5\)
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Answer & Solution

Correct Answer

(B) \(3\)

Step-by-step Solution

Detailed explanation

\(\ell=(\underbrace{1+\frac{2}{3}+\frac{6}{3^{2}}+\frac{10}{3^{3}}}_{\mathrm{s}}+\ldots)^{\log _{(0.25)\left(\frac{1}{3}+\frac{1}{3^{2}}+\ldots\right)}}\) \(S=1+\frac{2}{3}+\frac{6}{3^{2}}+\frac{10}{3^{3}}+\ldots\)…
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