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JEE Mains · Maths · STD 12 - 13. probability

समुच्चय \(\{1,2,3,4, \ldots ., 100\}\) में से एक संख्या \(x\) यादृच्छया चुनी गई। घटना \(A\) को परिभाषित कीजिए : \(A =\) चुनी गई संख्या \(x\) \(\frac{(x-10)(x-50)}{(x-30)} \geqslant 0\) को संतुष्ट करती है। तो \(P ( A )\) है 

  1. A \(0.71\)
  2. B \(0.70\)
  3. C \(0.51\)
  4. D \(0.20\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.71\)

Step-by-step Solution

Detailed explanation

Given \(\frac{(x-10)(x-50)}{(x-30)} \geq 0\) Let \(x \geq 10, x \geq 50\) equation will be true \(\forall x \geq 50\) as \(\left(\frac{x-50}{x-30}\right) \geq 0, \forall x \in[10,30)\) \(\begin{array}{c}{(x-10)(x-50)} \\ {x-30}\end{array} \geq 0 \forall x \in[10,30)\) Total…
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